Question

1
If p(x)=x2-7x+6 then find the values of p(1),p(4)​

Answer 1

Answer:

p(1) = 0

p(4) = -6

Step-by-step explanation:

p(x) = x^2 -7x + 6

p(1) = 1 -7 + 6 = 0

p(4) = 16 -28 + 6 = 22-28 = -6

Answer 2

P(x) = x² - 7x + 6

• P(1) = 1² - 7 x 1 + 6

1 - 7 + 6 = 0

• P(4) = 4² - 7 x 4 + 6

16 - 28 + 6 = - 6