Question

1) if p (X) = x² - x² + x + 1, then the value of P(-1) +PC).
2
es​

Answer 1

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$p(x) = {x}^{3} - {x}^{2} + x + 1$

$p( - 1) = {( - 1)}^{3} - {( - 1)}^{2} +( - 1) + 1 \\ = - 1 - 1 - 1 + 1 \\ = - 1$

$p(1) = {1}^{3} - {1}^{2} + 1 + 1 \\ = 1 - 1 + 1 + 1 \\ = 2$

Now,

$\frac{p( -1) + p(1)}{2}$

$\frac{ - 1 + 2}{2}$

$\frac{1}{2}$

Answer 2

Answer:

is 2

Step-by-step explanation:

p(1) = 1-1 +1+1

= 2

p(-1) = 1-1 +1+1

=2

$\frac{p( - 1) + p(1)}{2} = \frac{2 + 2}{2} \\ = \frac{4}{2 }$

= 2