Question

1.IF P(X)=x3+2x2-5x-6 , then p(-1) will be: a)3 b)2 c)5 d)o​

Answer 1

Answer:

d) 0

Step-by-step explanation:

p(x) = x^3 + 2x^2- 5x - 6

So, p(-1) = (-1)^3 + 2(-1)^2 - 5(-1) - 6

= -1 + 2 + 5 - 6

= 0

Answer 2

Answer:

Option d) is the correct answer.

The value of$p(-1)$ will be 0.

Step-by-step explanation:

Given: $P(x)=x^3+2x^2-5x-6$

We have to find the value of$p(-1)$.

We are solving in the following way:

We have,

$P(x)=x^3+2x^2-5x-6$

To find the value of$p(-1)$, we will put the value of$x=-1$ in$P(x)=x^3+2x^2-5x-6$.

Now,

$P(x)=x^3+2x^2-5x-6$

$=>P(-1)=(-1)^3+2\times(-1)^2-5\times(-1)-6\\=>P(-1)=-1+2\times1+5-6\\=>P(-1)=-1+2-1\\=>P(-1)=1-1\\=>P(-1)=0$

In this problem, we are assuming the given equation as:

$P(x)=x^3+2x^2-5x-6$

Q. If $P(x)=x^3+2x^2-5x-6$then p(-1) will be: a)3 b)2 c)5 d)0​