Question

1). if polynomials ax^3+4x^2+3x-4 and x^3-4x+a leave same remainder when divided by x-3,find a

2). 3^2x × 3^2x/ 3^2 = 4√3x-4.

3). Evaluate 4/(216)^-2/3 + 1/(256)^-3/4 + 2/(243)^ 1/5
(please answer, its urgent)​

Answer 1

Answer:

1) a=-1

Step-by-step explanation:

1) let x-3=0 => x=3

ax^3+4x^2+3x-4 = x^3-4x+a

a(3)^3+4(3)^3+3(3)-4 = 27-12+a

27a+36+9-4 = 27-12+a

27a+41 = 15+a

27a-a = 15-41

26a = -26

a = -1