Question

1. If PT is the tangent at the point to the circle with centre O, if OT=6 cm and OP=10cm, then
the length of the tangent PT is​

Answer 1

Answer:

8

Step-by-step explanation:

(op)^2=(ot)^2+(tp)^2.

100=36+(tp)^2

100-36=(tp)^2

64=tp^2

8=tp

tp=8

Answer 2

Answer:

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