Question

1. If sec e = 13, find sin and cot 0.

Answer 1

Answer:

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Answer 2

Answer:

sec e = 13

sec theta = hypotenuse/opposite

sec e` = 13

In ∆ ABC,

AB = 13

BC = 1

By Pythagoras theorem,

AB^2=BC^2+AC^2

169= 1 + AC^2

168= AC^2

√168= AC.

sin e = √168/13

cot e = 1/ √168