Question

1. If sin 0=4/5
find cos 0 and tan O.
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Answer 1

Answer:

$\sin( \alpha ) = \frac{4}{5}$

Pythagoras theorem

(5k )²=( 4k )²+ x² ( x here is the adjacent side )

25k² = 16k² + x²

9k² = x²

x = 3k

so

$\cos( \alpha ) = \frac{3}{5}$

and

$\tan( \alpha ) = \frac{4}{3}$

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Answer 2

Answer:

P = 4

H = 5

B = ?

P^2 + B^2 = H^2

(4) ^2 + B^2 = (5) ^2

B =

$( \sqrt{25 - 16} ) ^{2}$

B =√9

B = 3

Cos O = B / H = 3/5

Tan O = P/ B = 4 / 3

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