Question

1. If sin 2a = A sin 2(a +ß), A60, then--
(i) tan2a
A sin 28
A sin 2ß
A
B)
1 - A cos 2B
1 + A cos 2B
A cos 2ß
A sin 28
1 - A sin 23
1 + A cos 2B
(ii) tan 28 =
sin 2a(1 + Acos 2ß)
(А)
A cos 2a cos 23
(В
sin 2a(1 - Acos 28)
A cos 2a cos2B
cos2a(1 + A sin 2B)
A cos 2a cos 2B
cos2a(1 - A sin 2ß)
A cos 2a cos 2ß
D​

Answer 1

Answer:

I can't understand what are you written