Question

1 If sina = 3/5, find COSA & TanA​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

We know sin^2 + cos^2 = 1

(3/5)^2 + cos^2 =1 Subtract (3/5)^2 on both sides

cos^2 = 1 - (3/5)^2 Simplify(3/5)^2

cos^2 = 1 - (9/25) Simplify

cos^2 = 16/25 Take the square root of both sides

cos = (+0r -) 4/5

But we know cos<0 so only -4/5 will work.

Tangent is sin/cos, so tan = (3/5)/(-4/5) simplify by multiplying by one in the form of (1/5)/(1/5) which leads to the result that tan A=(-3/4) or -0.75