Question

1) If sinx + cosx = 1
find the value of sin2x
2) Find maximum value of
sinx + cosx
3) Find the range of 2sinx.
​

Answer 1

Answer:

3) range is -1/2 to +1/2

2) maximum value is 1

1) 1/2+cosx/2

Answer 2

Answer:

(sinx+cosx) ^2 =sin^2 x+cos^2 x+sin2x=1

1+sin2x=1

Sin2x=0

Maximum value of sin x+cos x=v(1+1)=v2

Range of 2 sin x=[-2,2]