Question

1. If tan 50.tan 4 0 = 1 then 0=​

Answer 1

Answer:

Step-by-step explanation:

A=theta'0'

tan 5A .tan 4A=1

tan 5A = 1/ tan 4A (1/tanA =cot A)

tan 5A=cot 4A (cot A =tan(90-A)

tan 5A=tan (90 - 4A)

5A=90 -4A

5A+4A=90

9A =90

A=10

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