1. If tan A = 1, show that sin A cos A = 1/2 (Using Pyth )
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Answered by
9
Solution :-
Given ,
- tanA = 1
We need to show that ,
- sinA cosA = 1/2 [ Using Pythagoras theorem ]
If tanA = 1 height of triangle is 1 & base of triangle is 1 .
Now , finding hypotenuse using Pythagoras theorem .
Hyp² = Base² + Height²
→ Hyp² = 1² + 1²
→ Hyp² = 1 + 1
→ Hyp² = 2
→ Hypotenuse = √2
• sinA = opposite/Hypotenuse
• cosA = Adjacent/Hypotenuse
♦ sinA = 1/√2
♦ cosA = 1/√2
Now finding, sinA cosA
⇒ 1/√2 × 1/√2
⇒ 1/(√2)²
⇒ sinA cosA = 1/2
Hence , sinA cosA = 1/2
Cynefin:
Awesome :)
Answered by
128
♣ Qᴜᴇꜱᴛɪᴏɴ :
- If tan A = 1, show that sin A cos A = (Using Pythagoras Theorem )
★═════════════════★
♣ ᴛᴏ ᴘʀᴏᴠᴇ :
sin A cos A = (Using Pythagoras Theorem )
★═════════════════★
♣ ᴀɴꜱᴡᴇʀ :
We know :
Also :
If tanA = 1
- Base = 1
- Height = 1
According to Pythagoras Theorem :
Hypotenuse² = Height² + Base²
According To Question :
Hypotenuse² = 1² + 1²
Hypotenuse² = 1 + 1
Hypotenuse² = 2
Hypotenuse = √2
Now we need to Prove sin A cos A =
→ Taking L.H.S
sin A cos A
= R.H.S
★ Hence Proved ★
★═════════════════★
♣ ᴏᴛʜᴇʀ ᴛʀɪɢᴏɴᴏᴍᴇᴛʀɪᴄ ɪᴅᴇɴᴛɪᴛɪᴇꜱ :
- sin(θ) = Height / Hypotenuse
- cos(θ) = Base / Hypotenuse
- tan(θ) = Height / Base
- cosec(θ) = Hypotenuse / Height
- sec(θ) = Hypotenuse / Base
- tan(θ) = Base / Height
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