Question

1)If tan (A + B) =√3 and tan (A – B) =1/√3, 0° < A + B ≤ 90°; A > B, find A and B..
2) : Prove the identities:
(i) √[1 + sin A/1 – sin A] = sec A + tan A
(ii) (1 + tan2A/1 + cot2A) = (1 – tan A/1 – cot A)2 = tan2A. ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

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