Math, asked by someshtellakula, 8 months ago

1
if tanA = x+1, tanB = x-1, then 2 cot (A-B) =


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Answers

Answered by tarushbanke123
0

Answer:

please elaborate the question please

Answered by Vikassandeep
0

Answer:

Step-by-step explanation:

tanA=x+1 tanB=x-1

2cot(A-B)=2/tan(A-B)

2cot(A-B)=2(1+tanA.tanB)/tanA-tanB

2cot(A-B)=2(1+(x+1)(x-1))/x+1-x+1)

2cot(A-B)=2(1+x^2-1)/2

2cot(A-B)=X^2

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