Question

1. If the amount of charge passed in time t througha cross-section of wire is Q = 8t - 2t2, thenaverage current from t = 0 to t = 2 second is(1) OA(2) 4 A(3) 2A(4) 8 A6.​

Answer 1

The average current from t = 0 to t = 2 second is 0 A.

Explanation:

If the amount of charge passed in time t through a cross-section of wire is :

$Q=8t-2t^2$

We know that the rate of change of electric charge is called electric current such that,

$I=\dfrac{dQ}{dt}$

$I=\dfrac{d}{dt}(8t-2t^2)$

$I=8-4t$

Then the average current from t = 0 to t = 2 second is :

$I=8-4(2)-0$

I = 0 A

So, the average current from t = 0 to t = 2 second is 0 A. Hence, this is the required solution.

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Electric current

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Answer 2

Answer:

Explanation:

I=dq/dt

I=d(8t-2t^2)/dt

I=8-4t   ———(i)

AT t=0

I=8-4*0=8

I=8

AT t=2

I=8-4*2=0

I=0

I(avg)=8-0/2=4A

I(avg)=4A