Question

1.If the angle of elevation of the top a tower 200m high from two points A and B on the ground on elther side of the Tower are 45° and 30°erspectively, then the distance b/w the points A and B is:​

Answer 1

Refer the attachment

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Answer 2

Step-by-step explanation:

let the distance b/w the points=x,y

• In triangle ABC angle B =90
• tanQ=p/b
• tan30 =AB/CB
• 1/√3=200/y
• y=200√3
• In triangle ABD, B =90
• tan45=AB/BD
• 1=200/x+y
• x+y=200
• x=200-y
• x=200-200√3(from eq i)
• x=200(1-√3)meter