1.
If the area of isosceles trapezium whose parallel sides are 38.7 cm and 22.3 cm is 18372 sq. cm,
then find its other two non parallel sides.
Answers
Maths
The Triangle and Its Properties
Recalling Basics of Triangles and Its Types
If non - parallel sides of ...
MATHS
If non-parallel sides of an isosceles trapezium are prolonged, an equilateral triangle with sides of 6cm would be formed. Knowing that the trapezium is half the height of the triangle, calculate the area of the trapezium.
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ANSWER
R.E.F. Image.
we know attitude is also a median in equilateral triangle.
BG = GC = 3 cm.
from ΔABG by Pythagoras theorem.
(AB)
2
=(AG)
2
+(BG)
2
(6)
2
=(AG)
2
+(3)
2
(AG)=
36−9
AG=
27
=5.20cm.
Height of trapezium = 2.60 cm → (given in question ⇒
2
5.20
=2.60cm)
Area of trapezium -
2
(a+b)×h
=
2
(6+3)×2.60
=9×1.3=11.70cm
2
.
solution
Answer:
answer is 11.8
Step-by-step explanation:
the question is kinda wrong the number must have been 183√2 .
here u go the answer is
area of trapezium =1/2*(sum of parallel sides)*height
183√2=1/2*(38.7+22.3)*h
h=183√2*2/61
h=6√2(ae=h)
if abcd is trapezium and e and f are perpendicular then de= 38.7-22.3/2=8.2
ad=√ae^2+de^2=√6√2^2+8.2^2=11.8
For better understanding draw a diagram(sorry that I couldn't upload one)