1.
If the average of the first 'n' numbers in the
sequence 148, 146, 144, ........, is 125, then n =
Answers
Answered by
2
Answer:
Average of terms = (a+l)/2
125= (148+l)/2
l=102
also
l= a+(n-1)*d
here a=148,l=102,d=-2
hence
solving we get
n= 24
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Answered by
0
Answer:
n^2
Step-by-step explanation:
n×n =n^2
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