Question

1) If the base of a right-angled triangle is 16 cm and the hypotenuse is 20 cm, then find the height of that triangle?
2) If the square of the hypotenuse of an isosceles right triangle is 128 cm2. Find the length of each side.
3) Find the perimeter of the rectangle whose length is 15 m and the diagonal are 17 m.
4) A ladder 13 m long is placed on the ground in such a way that it ouches the top of a vertical wall 12 m high. Find the distance of the foot of the ladder from the bottom of the wall.

Answer 1

Answer:

1)

base of a right angled triangle =16cm ,

hypotenuse =20 cm,

hypotenuse square =base square + perpendicular square

(20)²=(16)²+perpendicular) ²

400-256=(perpendicular) ²

144=(perpendicular)²

√12*12=perpendicular

12 cm=perpendicular

Answer 2

Step-by-step explanation:

1. (20)^2=(16)^2+ (h)2

(h)^2=400 -256

h=13

2. 128= s^2+s^2

128=2(s^2)

s^2=64

s=8

3. l= 15

d=17

diagonal is considered as hypotenus

( d)^2 = ( l ) ^2 +(breadth)^2

b=8

perimeter= 2(l +b)

=2(23)

=46cm

4. length of ladder = 13cm

height of wall. = 12cm

distance from. = (13)^2 -(13l^2

wall to foot of

ladder is

d= 5cm