Question

1. If the concentration of glucose (C6H1206) in blood is 0.9 g L-1, what will be the molarity of
glucose in blood? (2M)
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Answer 1

Answer:

Molarity is the number of moles present in one litre of the solution. Here, mass is given as 0.9g. As we know the molar mass of glucose is 180g. Therefore, the molarity of the glucose solution is: 0.9/180 = 0.005 moles/L.

Answer 2

Answer:

Morality, M = 0.005 mol L^-1

Explanation:

Given,

C6H12O6 is solute and blood is solution

Glucose mole = (Given mass) / (Molecular mass)

Glucose mole = 0.9 g / 180 g

                       = 0.005 mol

We know that,

Morality, M = (Mole of solute) / (Litre in solution)

                  = 0.005 mol / 1 L

                  = 0.005 mol / L

                                                    Solved by

                                             Aaditya Singh