1). If the density of ice be 0.91 g/cc then what will be the volume of water when it frozen to ice of volume 1000 cm3.?
2) An iron block of mass 25.6 kg and volume 3280 cm3. Find it's density.
3). A block of aluminium of density 2.75 g/cm3 has volume 40 cm3. Find the mass of block in SI unit.
4). The pendulum of a Bob completes 20 Oscillations in 41 sec. Calculate its time period and frequency.
5) Rahul completes 500 m race in 30 sec. Calculate its speed in km/hr unit.
6). Aditya cycles to school at a speed of 25 km/hr. His school is of 10 km away. How long will he take to reach there?
7). A car travels from town A to tow n B that is of 250 km in 3hrs 30min and from B to C in 2hrs 40 min. The distance between B and C is 150 km. Find the average speed of the car.
8) Your class is going out on a picnic far away from your school. The class leaves in two groups. The first group Leaves by a bus and second group by a train. If there is no disruption of traffic which group will reach first? Explain it.
9) Find the mass of 2.5 litres of alcohol in mg unit when density of alcohol is 0.8 g/cc
10). Convert the volume 2.6 cubic cm in cubic mm unit.
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Answer:
The density of a substance is its mass divided by its volume:
d=m/V
Ice is less dense than liquid water so 1000 ml of liquid water, when frozen, will have a greater volume. (Note that the unit ml is equivalent to cm^3 or cc.)
In order to solve this problem we need to know the density of water, which isn't given. Water's density varies slightly with temperature. The value often used is 1.00 g/cm^3 at a temperature of 25 degrees C. We'll use this value to solve the problem since temperature isn't given.
1. The mass of ice is equal to the mass of liquid water, which we can calculate as follows:
d = m/V, so m = d x V
m = (1.00 g/cm^3)(1000 cm^3) = 1.00 gram
2. Find the volume of 1.00 g ice:
V = m/d = (1.00g)/(0.91 g/cm^3) = 1.10 cm^3
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