Question

(1)
If the
equation x² - bx + 1 = 0
dou
not possess real
roots
then​

Answer 1

Answer:

equation x2−bx+1=0 does not have real roots, then 

Δ<0⟹b2−4<0

(b+2)(b−2)<0

∴−2<b<2

I hope it will help you

Answer 2

Step-by-step explanation:

If it doesn't possess real roots its discriminant should be negative

${b}^{2} - 4ac < 0$

So

$( { - b)}^{2} - 4(1)(1) < 0$

${b}^{2} - 4 < 0$

Or you can say that

$b < + 2 \: or \: - 2$