1. If the length of a double helical DNA is 1.7 meters. The
number of base pairs present in the DNA is
(a) 5 x 10^9
(b) 1.7 x 10^9
(c) 3.4 x 10^9
(d) 1.7 x 10^5.
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Answer:a) 5×10^9
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