Question

(1) If the lengths of diagonals of rhombus are 11.2 and 7.5 cm then its area is
(A) 42 sq. cm
(B) 42 cm
(C) 84 sq. cm
(D) 84 cm​

Answer 1

Explanation:

the lengths of diagonals of rhombus are 11.2 and 7.5 cm then its area is

(A) 42 sq. cm

(B) 42 cm

(C) 84 sq. cm

(D) 84 cm

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Answer 2

Answer:

Given :

Perimeter of a trapezium is 152 m

Non-parallel sides of a trapezium are 18 m and 24 m

Height of a trapezium = 12 m

To Find :

Area of trapezium.

Calculations :

Firstly let's calculate the length of non-parallel sides of a trapezium,

$\mapsto \sf 18 + 24 \: m$

On adding the numbers,

$\mapsto \rm{ \green{42 \: m}}$

So, length of non-parallel sides of a trapezium is 42 m.

Now, let's calculate the length of non-parallel sides, so in order to calculate non-parallel sides, we need to perform subtraction in :-

Perimeter of trapezium (152 m) - total length of parallel sides (42 m)

So, let's find the length parallel sides of a trapezium,

$\mapsto \sf 152 \: m - 42 \: m$

On subtracting the numbers,

$\mapsto \rm{ \green{110 \: m}}$

So, the length of parallel sides of a trapezium is 110 m.

According to the Question,

Now, let's calculate the area of trapezium, In order to find the area of trapezium,

Formula to be used :

$\boxed{\rm{ \pink{{Area_{(Trapezium)} = \dfrac{1}{2} \times Sum \: of \: parallel \: sides \times height}}}}$

$\dag$ Putting the values,

$\mapsto \sf Area_{(Trapezium)} = \dfrac{1}{2} \times 110 \: m \times 12 \: m \\ \\ \mapsto \sf Area_{(Trapezium)} = 55 \: m \times 12 \: m \\ \\ \mapsto \sf \boxed{ \bf{Area_{(Trapezium)} = 660 \: m^2 }} \: \pink{\bigstar}$

Henceforth,

Area of trapezium is 660 m².