(1) If the lengths of the sides of a triangle are in the ratio 3:4:5 and its perimeter is
48 cm, find its area.
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96cm2
perimeter of ∆=sum of 3sides
3x+4x+5x=48 cm
12x=48
x=4 cm
hence length of sides are=3*4=12,4*4=16,5*4=20
NOW by heron formula = √s(s-a)(s-b)(s-c)
=√24(24-12)(24-16)(24-20)
=√24*12*8*4
=√9216
=96cm square.
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