Question

1) If the point of intersection of ax + by=7 and bx + ay = 5 is (3,1), + Find the values of 'a' and 'b'.​

Answer 1

Answer:

(3,1) lies on ax + by = 7

Thus, 3a + b = 7.eq(i) and

it lies on bx + ay = 5

Thus, 3b + a = 5.eq.(ii)

Multiply (i) by 3 and subtractng both equations

9a+3b=21

a+3b=5

− − −

_______________ ________

8a = 16

a = 2

hence, b = 1

Hence value of a is 2

Answer 2

Answer:

Here's your answer mate

Step-by-step explanation:

(3,1) lies on ax + by = 7

Thus, 3a + b = 7 Equation 1

it lies on bx + ay = 5 Equation 2

Thus, 3b + a

Multiply (i) by 3 and subtractng both equations

9a+3b=21

a+3b=5

8a = 16

a = 2

hence, b = 1

Hence value of a is 2