Chemistry, asked by lokeshsharma8081, 1 year ago

1. If the rate of reaction increases by 27 times, when the temperature is increased by 30 K then temperature coefficient of the reaction is











a. 3 b. 2 c. 1 d. 2.5

Answers

Answered by anuj1920
38
Temperature coefficient of the reaction is given by :
Temperature coefficient(n) = Rate constant at Temperature (T+10) KRate constant at Temperature T K        ...........  eq 1 

similarly we can write:
n= Rate constant at Temperature (T+20) KRate constant at Temperature (T+ 10 )K        ...........  eq 2

n = Rate constant at Temperature (T+30) KRate constant at Temperature (T+20) K        ...........  eq 3 

Multiplying eq1 , eq2 and eq3, we get :

n3 = Rate constant at Temperature (T+30) KRate constant at Temperature T K 

Since it is given that rate of the reaction becomes 27 times at temperature T+30 K Thus we have, 

Rate constant at Temperature (T+30) KRate constant at Temperature T K  = 27

and hence ​n3 = 27
thus n = 3

Thus temperature coefficient of reaction is 3.
 
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