1. If the rate of reaction increases by 27 times, when the temperature is increased by 30 K then temperature coefficient of the reaction is
a. 3 b. 2 c. 1 d. 2.5
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Temperature coefficient of the reaction is given by :
Temperature coefficient(n) = Rate constant at Temperature (T+10) KRate constant at Temperature T K ........... eq 1
similarly we can write:
n= Rate constant at Temperature (T+20) KRate constant at Temperature (T+ 10 )K ........... eq 2
n = Rate constant at Temperature (T+30) KRate constant at Temperature (T+20) K ........... eq 3
Multiplying eq1 , eq2 and eq3, we get :
n3 = Rate constant at Temperature (T+30) KRate constant at Temperature T K
Since it is given that rate of the reaction becomes 27 times at temperature T+30 K Thus we have,
Rate constant at Temperature (T+30) KRate constant at Temperature T K = 27
and hence n3 = 27
thus n = 3
Thus temperature coefficient of reaction is 3.
Temperature coefficient(n) = Rate constant at Temperature (T+10) KRate constant at Temperature T K ........... eq 1
similarly we can write:
n= Rate constant at Temperature (T+20) KRate constant at Temperature (T+ 10 )K ........... eq 2
n = Rate constant at Temperature (T+30) KRate constant at Temperature (T+20) K ........... eq 3
Multiplying eq1 , eq2 and eq3, we get :
n3 = Rate constant at Temperature (T+30) KRate constant at Temperature T K
Since it is given that rate of the reaction becomes 27 times at temperature T+30 K Thus we have,
Rate constant at Temperature (T+30) KRate constant at Temperature T K = 27
and hence n3 = 27
thus n = 3
Thus temperature coefficient of reaction is 3.
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