1) If the ratio of the curved surface areas of solid cone and a solid right circular cylinder having same base radii and same height is 5:8, then let us determine the ratio of their base radii and height.
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Let the same base radii be r units and same height be h units
Given:-
Ratio of CSAs of cone and cylinder with same height and base = 5 : 8
- CSA of cone = πrl sq.units
- CSA of cylinder = 2πrh sq.units
⇒ πrl / 2πrh = 5 / 8
⇒ l / 2h = 5 / 8
We know that
- l = √( r² + h² )
⇒ √( r² + h² ) / 2h = 5 / 8
Squaring on both sides
⇒ [ √(r² + h²) / 2h ]² = ( 5 / 8 )²
⇒ ( r² + h² ) / 4h² = 25 / 64
⇒ 64r² + 64h² = 100h²
⇒ 64r² = 100h² - 64h²
⇒ 64r² = 36h²
⇒ r² / h² = 36 / 64
⇒ ( r / h )² = 36 / 64
Taking square root on both sides
⇒ √( r / h )² = √( 36 / 64 )
⇒ r / h = 6 / 8
⇒ r / h = 3 / 4
⇒ r : h = 3 : 4
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