Question

1.
If the roots of x^2+x+a=0 exceed a, then
a) 2 <a<3
b) a > 3
c)-3 < a <3
d)a<-2​

Answer 1

Answer:

d)a<-2

Step-by-step explanation:

x^2+x+a= 0

x^2+x-2=0

x^2+2x-x-2=0

x(x+2)-1(x+2)=0

(x+2)(x-1)=0

so, a<-2

Answer 2

Step-by-step explanation:

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