1 If the side of a square is increased by 20%. Then its area is increased by (A) 20% (B) 40% (C) 25% 44%
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Side is increased by 20%
let initial length of side be x.
increased length =x+20%(x)
=1.2x
initial area = x(x)=x2
increased area = (1.2x)(1.2x)=(1.44x2)
percent increase in area= x21.44x2−x2×100
=0.44×100
percentage increase in are =44%
so... option d) 44%
hope it helps...
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what is that lol hard right?
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