Question

1.
If the sides of a triangle are 5,6,10, then the length of the median of biggest side is​

Answer 1

Answer:

I really Dont know the answer

Answer 2

your question has mistake....plzzz correct it

• if sides of triangle are 5 6 10 then the square of length of the median of biggest side

$\mathsf{Using \: Apollonius \: Theorem, \: Median \: of \: triangle \: is \: calculated}$

$m_a\mathsf{= \: \frac{1}{2} \sqrt{2{b}^{2} + 2{c}^{2} - {a}^{2}}}$

$m_b\mathsf{= \: \frac{1}{2} \sqrt{2{a}^{2} + 2{c}^{2} - {b}^{2}}}$

$m_c\mathsf{= \: \frac{1}{2} \sqrt{2{a}^{2} + 2{b}^{2} - {c}^{2}}}$

$\mathsf\green{☆ \: We \: need \: to \: find \: length \: of \: median \: of \: longest \: side}$

$\mathsf\red{Given}$

$\mathsf\red{a \: = \: 10 \: \: b \: = \: 5 \: \: c \: = \: 6}$

$\mathsf\red{then ,}$

$m_a\mathsf{= \: \frac{1}{2} \sqrt{2{b}^{2} + 2{c}^{2} - {a}^{2}}}$

$m_a\mathsf{= \: \frac{1}{2} \sqrt{2×{5}^{2} + 2×{6}^{2} - {10}^{2}}}$

$m_a\mathsf{= \: \frac{1}{2} \times \sqrt{2(25) + 2(36) - (100)}}$

$m_a\mathsf{= \: \frac{1}{2} \times \sqrt{50+72-100}}$

$m_a\mathsf{= \: \frac{1}{2} \times \sqrt{22}}$

$\mathsf\red{☆ \: squaring \: on \: both \: sides \: we \: get }$

${m_ a}^{2}\mathsf{= \: \frac{1}{4} \times {22}}$

${m_a}^{2}\mathsf{= \: 5.5}$