Math, asked by Anonymous, 9 months ago

1) If the simple interest on ₹3200 by ₹108 in 3 years .Find the rate of interest

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Answered by Anonymous

$simple \: interest \: = \frac{principle \: \times \: rate \: of \: interest \: \times \: time \: peirod }{100}$

$simple \: interest \: = \frac{p \: \times \: r \: \times \: t}{100}$

$108 = \frac{3200 \: \times \: r \: \times \: 3}{100}$

$r \: = \: \frac{108 \: \times \: 100}{3200 \: \times \: 3}$

here 2 zeros of 100 & 3200 gets cancelled

108 & 3 gets cancelled

$r \: = \: \frac{36}{32} = \: \: \: \: r \: = \: \frac{18}{16} \: \: \: \: = \: \: \: \: \: r = \: \frac{9}{8}$

$r \: = \: 1.125\%$

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1) If the simple interest on ₹3200 by ₹108 in 3 years .Find the rate of interest​

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Hey Shreya

1) If the simple interest on ₹3200 by ₹108 in 3 years .Find the rate of interest