Question

1. If the sum of the roots of the equation 3x2-(3k-2) x-(k-6) = 0 is equal
to the product of its roots, then calculate k?​

Answer 1

Step-by-step explanation:

sum of root = -b/a

product of root = c/a

a/q

sum of root = product of root

-b/a = c/a

-b=c

-{-(3k-2)}= -(k-6)

3k-2= -k+6

4k=8

k=2

#666