Question

1. If the sum of three numbers in an A.P. is 9 and their product is 24, then
numbers are
(a) 2, 4, 6 (b) 1, 5, 3 (c) 2, 8, 4 (d) 2, 3, 4

Answer 1

Answer:

(d)2,3,4

Step-by-step explanation:

let the three numbers of A.P be a-d, a and a+d

ATQ,

a-d+a+a+d=9

=>3a=9

=>a=9/3=3

and,

(a-d)a(a+d)=24

=>(3-d)3(3+d)=24

=>3(3-d)(3+d)=24

=>3(9-d²)=24

=>9-d²=24/3=8

=>d²=9-8=1

=>d=√1=+1 or -1

let's take d=+1

then the A.P is

a-d=3-1=2

a=3

a+d=3+1=4

so the AP is 2,3,4