1.If the supplement of an angle is three times its complement , find the angle 2.if the complement of an angle is one third of its supplement ,find its angle 3.X lies in the interior of angle BAC . if < BAC=70. and
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1) Let angle be x.
Its supplement will be 180-x.
Complement of angle will be 90-x.
According to Q's:
=> 180-x= 3(90-x)
=>180-x= 270-3x
=> x= 45
(2) Let angle be x.
Its supplement will be 180-x.
Complement of angle will be 90-x.
According to Q's:
=> (90-x)= 1/3(180-x)
=> 180-x= 3(90-x)
=>180-x= 270-3x
=> x= 45
Its supplement will be 180-x.
Complement of angle will be 90-x.
According to Q's:
=> 180-x= 3(90-x)
=>180-x= 270-3x
=> x= 45
(2) Let angle be x.
Its supplement will be 180-x.
Complement of angle will be 90-x.
According to Q's:
=> (90-x)= 1/3(180-x)
=> 180-x= 3(90-x)
=>180-x= 270-3x
=> x= 45
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