Question

1) If the velocity of the body in motion of a particle is governed by the equation V= 2t3+(-3t)2+2t+2 Then find out the acceleration of the particle at t=4s and calculate the distance covered during the interval 3 sec to 6sec​

Answer 1

Answer:

acceleration at t=4 sec is 74ms^-2

Explanation:

explaination is above in pic