Physics, asked by puspendrasarmapkc9, 9 months ago

1
If уз
then y dx will be:
ax + b
(1)
+C
(2) ax + b + c
(ax + b)2
In(ax +b)
+
+C
(4)
(3) aln(ax+b)+C
a
1​

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Answers

Answered by FehlingSolution
9

Let ax + b = t

=> a = dt/dx

=> dx = dt/a

Substitute the value of dx in

 \int \frac{1}{ax + b} dx

we get,

 \int \frac{dt}{at}

 =  \frac{1}{a}  \int \frac{dt}{t}

 =  \frac{1}{a}  log(t)  + c

substitute the value of t in above expression

 \frac{1}{a}  log(ax + b)  + c

Thus, correct option : 4) [ln(ax+b)]/a + c

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