1. If three arithmetic means are inserted between — 15 and 9, What is the first of the arithmetic.
A. 3
B. - 3
C. - 9
D. 6
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First term =-15
Second term is 9
Tn=a×(n-1)d
If you insert 3 arithmatic means between them 9 WIILL be T5 of AP
T5=T1+(5-1)×d
9=T1+4d
9=-15+4d
4d=24
d=6
a=--15 d=6
The terms of AP are
-15 -15+6 - 15 +2×6 -15 +3× 6 -15+4×6
-15 -9 -3 3 9
First AM is --9
Explanation step by step
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