Question

1) If TP and TQ are two tangents to a circle with centre 0, so that
POQ = 120°, then find ZPTQ.​

Answer 1

Answer:

here's your answer

Step-by-step explanation:

Given,

∠PTQ = 120°

∠OPT=∠OQT=90° ( the point where the tangent touches the circle forms 90° angle with the radius)

Also, TPOQ is a quadrilateral

Then,

∠POQ+∠OQT+∠QTP+∠TPQ=360°

120°+90°+90°+∠PTQ=360°

∠PTQ=360°-300°

         =60°

Therefore,

∠PTQ=60°