Question

1) if triangle ABC - triangle PQR , and AB: PQ=2:3 then complete the following​

Answer 1

Question :-

If ∆ABC ~ ∆PQR and AB:PQ = 2:3, then what is

$\frac{area(∆ABC)}{area(∆PQR)} = \: \: \: ?$

Answer :-

We know that,

→ If two triangles are similar then the ratio of their areas is equal to the ratio of the square of their corresponding sides.

So,

$\frac{area(∆ABC)}{area(∆PQR)} = \: \: \: {(\frac{AB}{PQ})}^{2}$

$= { (\frac{2}{3} )}^{2} = \frac{4}{9}$

So, the ratio of the areas of the two similar triangles ABC and PQR is

$\frac{area(∆ABC)}{area(∆PQR)} = \frac{4}{9}$

Hope it helps...