1. If two numerical equal forces P and p acting at a point produce a resultant force of magnitude
P itself, then the angle between the two original forces is
(A) 0°
(B) 60°
(C) 90°
(D) 120°
with process
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Hey Dear,
● Answer -
(B) θ = 60°
◆ Explanation -
Let P & p be two forces with equal magnitude.
Magnitude of resultant force due to both forces acting at same point is given by -
F = √(P² + 2P.p.cosθ + p²)
But Given that, p = P = F, now -
P = √(P² + 2P.P.cosθ + P²)
P² = 2P² (1 + cosθ)
1 + cosθ = 1/2
cosθ = 1 - 1/2
cosθ = 1/2
Taking cos inverse,
θ = arccos(1/2)
θ = 60°
Therefore, the angle between two original forces is 60°.
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