1. If x = 1/2, y = −2/3 and z = 1/4, verify that x × (y × z) = (x × y) × z.
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Given
x=4/9,y=−7/12,z=−2/3
x−(y−z)
=(x−y)−z
L.H.S.=x−(y−z)
=4/9−{−7/12−(−2/3)}
=4/9−(−7/12+2/3)
On further calculation, we get
=4/9−{(−7+8)/12}
=4/9−(1/12)
=4/9−1/12
Taking L.C.M. we get,
=(16−3)/36
=13/36
Now,
R.H.S=(x−y)−z
={4/9−(−7/12)}−(−7/12)
=(4/9+7/12)+7/12
On further calculation, we get
={(16+21)/36}+7/12
=37/36+7/12
Again taking L.C.M. we get,
=(37+21)/36
=58/36
Therefore, x−(y−z)
=(x−y)−z.
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