Question

1. If x=2, find the value of
(a) 25+x
(b) x²–5
(c) x²+4x+4
(d) 8upon3x–1upon6​

Answer 1

Step-by-step explanation:

1) 25+x

= 25+2

= 27

$2) {x}^{2} - 5$

$= ( {2})^{2} - 5$

$= 4 - 5$

$= - 1$

$3) {x}^{2} + 4x + 4$

$= ( {2})^{2} + 4 \times 2 + 4$

$= 4 + 8 + 4$

$= 16$

Answer 2

(a) If x = 2 then,

25 + x = 25 + 2 = 27

(b) If x = 2 then,

x² - 5 = (2)² -5 = 4 - 5 = -1

(c) If x = 2 then,

x² + 4x + 4 = (2)² + 4(2) + 4 = 4 + 8 + 4 = 16

(d) If x = 2 then,

8/3x - 1/6 = 8/ 3(2) - 1/6 = 8/6 - 1/6 = 8-1/6 = 7/6

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