Math, asked by golujain, 1 year ago

1. If x+2y+3z=0
x^2+4y^3+9z^3 = 18 xyz : evaluate ;
(x+2y/xy)^2 + (2y+3z/yz)^2 + (3z+x/zx)^2


ans is 18​

Answers

Answered by Anonymous
1

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