Question

1) IF X-3 IS A FACTOR OF Xx2-6K+ 12, THEN FIND THE VALUE OF K.

2) IF X-3 FACTOR OF PX2 + 5x + 6, THEN FIND THE VALUE OF P.


Answer it properly and step by step ​

Answer 1

Answer:

1) x-3 = 0

x = 3

f(x) = 3

•°• x² -6K +12 = 0

3²-6K + 12 = 0

9 +12 = 6K

K = 21/6

K = 7/2

•°• the value of k = 7/2

2) x-3=0

x= 3

f(x) = 3

x²P +5x+6 =0

3²p +5×3 +6 = 0

9p +15 +6 =0

9p +21 =0

9p = -21

P = -21/9

P = -7/3

•°• the value of P is -7/3

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Answer 2

Answer:

Sorry for answer but

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