Question

1
If x=3 sin 0 4 4 cos 0 and y 3 cos 0 - 4 sin 0 then prove that *2 + y2 = 26.​

Answer 1

Answer:

Step-by-step explanation:

Step-by-step explanation:

let theta be 'a'

x=3sin(a)+4cos(a)

y=3cos(a)-4sin(a)

x^2+y^2= {3sin(a)+ 4cos(a)}^2+ {3cos(a)-4sin(a)}^2

=>>9sin^2(a) +16cos^2(a) +24sin(a)cos(a)+ 9cos^2(a) + 16sin^2(a)-24sin(a)cos(a)

=>>>9{sin^2(a)+ cos^2(a)}+ 16{sin^2(a) +cos^2(a)}

=>>>9+16. { sin^2(a)+cos^2(a) =1}

=>>>>25

Answer 2

the answer is 26

Step-by-step explanation:

first first + the 3 cos 0 - 4 is equal to answer 7 and - 44 it is your answer 37 then minus x = 3 is your answer is 34 then *2 + y2 is is equal to answer is 4 then the 34 - 2 your answer is 32 was coming then one more time 32 - 2 then your answer is 30 then 30 - 4 is equal to answer is 26

I hope it was help you