1. If x= 3k+2 and y=2k-1 is a solutioin of the equation 4x-3y+1=0, find the value of k.
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It is given that
4x - 3y + 1 =0
Now by substituting the value of x and y in the equation .
4(3k + 2) - 3(2k - 1 ) + 1 =0
On further calculation
12k + 8 - 6k + 3 + 1 = 0
6k + 12 = 0
So we get
6k = -12
By division
k=-2
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4x - 3y + 1 =0
Now by substituting the value of x and y in the equation .
4(3k + 2) - 3(2k - 1 ) + 1 =0
On further calculation
12k + 8 - 6k + 3 + 1 = 0
6k + 12 = 0
So we get
6k = -12
By division
k=-2
MARK ME AS A BRAINLIEST
HOPES IT HELPS YOU!
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