Question

1) if x is equal to 3 by 2 is a zero of 6 x square minus kx minus 3 then find k and the remaining zero.
2) if alpha and beta are the zeros of 2 x square - 3 x - 5 then find Alpha square plus beta square and 1 by alpha + 1 by beta.
3) write a quadratic polynomial whose product of the zero and the sum of the Zero are 3 by 4 and -1 by 2 respectively.

Answer 1

Answer:

K=-27/4

Step-by-step explanation:

Correct option is

A

−3 or −

4

27

⇒2α

2

+kx−5=0

α+β=−

2

k

, αβ=−

2

5

→x

2

−3x−4=0

⟹x

2

−3x−4=0

⟹x

2

−4x+x−4=0

⟹x(x−4)+1(x−4)=0

∴α=−1,β=4

If common root is −1,

∴β=

2

5

∴k=−3

If common root is 4

β=−

8

5

∴k=−

4

27