Question

1 If x + px - 30 = (x - 5)(x + 6), x,
find the value of p.​

Answer 1

let x=1

putx=1

1+p-30=(1-5)+(1+6)

-29+p=-4+7

-29+p=3

p=3+29

p=32

Answer 2

The value of p is 1.

Step-by-step explanation:

Since we have given that

$x^2+px-30=(x-5)(x+6)$

First we solve the second equation,

$(x-5)(x+6)=x^2+x-30$

When we equate this with the first equation, we get that

$x^2+px-30=x^2+x-30$

$p=1$

Hence, the value of p is 1.

# learn more:

If(x²+px-30)= (x-5)(x+6) Then the value of P Is

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