Question

1. If x + y = 12 and xy = 32, Find the value of x2
+ y2​

Answer 1

Answer:

x=16/121.

y=16384/121.

Step-by-step explanation:

x+y=12 eq 1

xy=32 eq 2

xy=32

x=y/32. sub on eq 1

y/32+y=12

y+32y/32=12.

33y=12*32

33y=384.

y=384/33

=128/11.

sub on eq 1

x+128/11=12

11x+128/11=12

11x+128=12*11=132

11x=132-128

11x=4

x=4/11

x²=(4/11)²=16/121.

y²=(128/11)²=16384/121.

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Answer 2

Answer:

given =.x+y = 12

xy=32

find $x^{2}+y^{2}=?$

x+y = 12 (squaring on both side)

$x^{2}+y^{2}+ 2xy = 144 \\ x^{2}+y^{2}+2×32 = 144 \\ x^{2}+y^{2}=.144-2×32 \\ x^{2}+y^{2}=80$......